Program using if-else statement to find the largest number in the given three numbers (If Else Statement).

Main()
{
int n,m,k;
printf(“Enter three numbers\n”);
scanf(“%d%d%d”,&n,&m,&k);
if((n>m)&&(n>k))
printf(“Greater no=%d\n”,n);
else
if(m>n&&m>k)
printf(“Greater no=%d\n”,m);
else
if(k>n&& k>m)
printf(“Greater no =%d\n”,k);
getch();
}


Posted by: Wasim Javed

Determine whether the number is positive or negative or zero(If Statement).

Main()
{
int num;
printf(“Enter the number\n”);
scanf(“%d”,&num);
if(num >0)
printf(“num is pocitve =%d\n”,num);
if(num<0)
printf(“num is negative =%d\n”,num);
if(num=0)
printf(“num is zero =%d\n”,num);
getch();
}


Posted by: Wasim Javed

Write a program to input the age of a person in years. Convert the age into months and days and print the result in the center of the screen

Main()
{
long int age,mon,days;
clrscr();
printf(“Enter age in years ?”);
scanf(“%d”,& age );
mon=age*12;
days=age*365;
gotoxy(35,12);
printf(“Age in months = %d”, mon);
gotoxy(35,13);
printf(“Age in days =%d”,days);
getch();
}


Posted by: Wasim Javed

Write a program to compute the area of a triangle

main()
{
int a,b,c;
double area, s;
a=115;
b=163;
c=210;
s=(a+b+c)/2..0;
area=sqrt (s* (s-a)* (s-b)* (s-c);
clrscr ();
printf( “/n Calculate Area= %f”,area);
}


Posted by: Wasim Javed

Program to declare and initialize data into string type variables name & city and print these variables on the screen by using the printf function.

main( )
{
char name [15]=”wasim javed”;
char city[25]=”D-I-khan”;
clrdcr ();
printf(“ Name: % s/n”,name);
printf(“city: % s/n”,city);
getch();
}


Posted by: Wasim Javed

Write a program to input a string by using “gets” function and thenprintit on the screen by using the “puts” fuction.

main( )
{
char str[20];
clrscr ();
puts (“Enter a string ? ”);
gets (str);
puts( The string is :”);
puts(str);
getch ();
}


Posted by: Wasim Javed

Kinetic Energy of a body of mass “m” moving with velocity “v” input the mass and velocity of a body during program execution(Kinetic Energy=1/2 mv^2).

main( )
{
float m,v,ke;
printf(“/n enter value of m,v”);
scanf(“%f % f”,&m,&v);
ke=1/2*m*v*v;
printf(
‘/n KR= %f “,ke);
}

Posted by: Wasim Javed

Program to compute the distance covered by a car in 50 seconds. The initial velocity is m/sec and acceleration is 5m/sec^2. Use formula s=vit+1/2 at^2

main( )
{
int t,vi,a;
double s;
t=50;
vi=10;
a=5;
s=vi*t+0.5*a*t*t;
clrscr ();
printf(“Distance Covered =%f m”,s);
}


Posted by: Wasim Javed

If a five digit number is input through the keyboard, write a program to reverse the number.

main( )
{
int n,r;
printf(“/n Enter a number”);
scanf(“%d”, &n);
Printf(“/n The number in revers”);
r= n%10;
n=n/10;
printf(“Reminder=%d”,r);
r=n%10;
n=n/10;
printf(“Reminder=%d”,r);
r=n%10;
n=n/10;
printf(“Reminder=%d”,r);
r=n %10;
n=n /10;
printf(“Reminder of r % d Reminder of n %d”,r,n);
}


Posted by: Wasim Javed

Temperature of a city in Fahrenheit degrees is input through the keyboard.Write a program to convert this temperature into centigrade degrees.

main( )
{
float f,c;
printf(“/n Enter temperature”);
scanf(“%f”,&f);
c=5.0/9.0*(f-32.0);
printf(“/n f=%f /t c=%f, fc);
}


Posted by: Wasim Javed

Find out the aggregate marks and percentage marks obtained by the student. Assume that the maximum marks that con be obtained in each subject is 100.

Main( )
{
int m1,m2,m3,m4,m5, sum;
float agg,per;
printf(“/n Enter the marks of five subjects”);
scanf(“% d % d % d %d % d “,&m1,&m2,&m3,&m4,&m5);
sum=m1+m2+m3+m4+m5;
agg=sum/5.0;
per=sum*100.0/500.0;
printf(“/n percentage =%f”,per);
}


Posted by: Wasim Javed

Write a program to input the age of a person in years. Convert the age into months and days and print the result in the center of the screen.

main( )
{
long int age, mon, day;
clrscr();
printf(“Enter age in years?”);
scanf(“%d”,&age);
mon=age * 12;
days= age *365;
gotoxy(365,12);
printf(“Age in days=%d”, days);
}


Posted by: Wasim Javed

If a four digit number is input through the keyboard. Write a program to obtain the sum of the first and last digit of this number.

main( )
{
int n,sum ,fd,ld;
Printf(“/n Enter the four digit number”);
Scanf(“%d”,&N);
Id=n%10;
Fd=n/1000;
Printf(“/n First digit is%d and last digit is “,fd,id);
Sum=fd+id;
Printf(“/n Sum of first and last digit =%d”,sum);
}

Posted by: Wasim Javed

Write a program to calculate the area & perimeter of the rectangle, and the area of circumference of the circle.

Main( )
{
int len, wid, r;
float por, aoc, coc;
float pi=3.1417;
printf(“/n Enter the value of length, width &radius “);
scanf(“%d %d %d “,&len, &wid, &r);
por=2*(len+wid);
aor=len+wid;
aoc=pi*r*r;
coc=2*pi*r;
prontf(“/n perimeter of rectangle is % f”,por);
Printf(“/n area of rectangle is %f”,aor);
Printf(“/n arear of circle is %f”,aoc);
Printf (“/n circumference of circle id %f”, coc);
}

Posted by: Wasim Javed

The distances between two cities (in km)is input through the keyboard write a program to convert and print this distance

main( )
{
float km,m ,ft,inc,cm;
printf(“/nEnter the distance b/w two cities in km”);
scanf(“%f”,&km);
m=km*1000;
cm=m*100;
inc=cm/2.54;
ft=inc/12
printf(“/n meter=%f/n centimeter/n %f”,m,cm);
printf(“/n inches=%f/n feet /n %f”,inc,ft);
}

Posted by: Wasim Javed

Nawaz basic salary is input through the keyboard. His dearness allowances us 40% of basic salary. Write a program to calculate his gross salary.

main( )
{
int b_pay;
float d all.h rent, g_pay
printf(“/nEnter The Basic Salary Of Employer”);
scanf(“%d%d”,&b,&pay”);
d_all=b_pay*40.0/100.0
g_pay=b_pay+d_all+h_rent;
Prnitf(“Gross salary of employer is= %f”,g_pay);
}

Posted by: Wasim Javed

Get two numbers display addition, subtraction, multiplication, division of the numbers.

main( )
{
float a,b, ad,sb,mul,div;
printf(“/n enter value of a,b”);
scanf(“%f%f”,&a,&b);
ad=a+b;
sb=a-b;
mul=a*b;
div=a/b;
printf(“/n addition =%f”,ad);
printf(“/n subtraction=%f”,sb);
printf(“/n multiplication =%f”,mul);;
printf(“/n division =%f”, div);
}

posted by: Wasim Javed

write a program to input a string by using “gets” function and then print it on the screen by using the “puts” function (Gets Function)

main( )
{
charstr[20];
clrscr();
puts(“/n Enter a string ?”);
gets(gets);
puts(“The string is”);
puts(str);
getch();
}


Posted by: Wasim Javed

String type variables name &city and print their contents on the screen in left –justified and in right –justified format with field width 30

main( )
{
char name[25]=”wasim javed”;
char city[25]=”D-I-khan”;
clrscr();
printf(“Left – justified /n”);
printf(“%-30s/n”,name);
printf(“%-30s/n”,city);
printf(“Right –justified /n”);
printf(“%-30s/n”,name);
printf(“%-30s/n”,city);
getch();
}

Posted by: Wasim Javed

Input the radius of a sphere. Compute its valume and surface area(“Formula for surface area=4 TT r2 and volume=4/3TTr3 and TT=3.1417(Scanf)

main( )
{
float r,v, area;
clrscr();
printf(“Enter radius of sphere?”);
scanf(“%F”,&r);
area=4.0*3.1417*r*r;
v=(4.0/3.0)*3.1417*r*r*r;
printf(“Volume of sphere =%f/n”,v);
printf(“area of sphere=%f/n”,area);
getch();
}


Posted by: Wasim Javed

write a program to declare and initialize the values to variables x,y&z of char type and then print their contents on screen by(Using printf Function)

main( )
{
char x=’r’ ,y=’n’ ,z =’b’;
clrscr ();
printf(“”Data in x=%c/n”,x);
printf(“”Data in y=%c/n”,y);
printf(“”Data in z=%c/n”,z);
}

Posted by: Wasim Javed

write a program to print a message on the screen by using the printf function (Printf Function)

main ( )
{
clrscr();
printf(“The casting vote of the speaker decided the matter”);
printf(“Examination proved a hard pill for me to swallow”);
getch();
}

Posted by: Wasim Javed

write a program in C to assign three values to three integer type variables r,n &b. Add variables r&n and multiply their sum to variable b

main ( )
{
int r,n, b;
clrscr();
r=2;
n=4;
b=6;
b *=r+n
printf(“Result =%d \n”,b);
getch();
}

Posted by: Wasim Javed

write a program to exchange the values of two variables using assignment and print the exchanged values on the screen( Arithmetic assignment)

main( )
{
int a,b,c;
clrscr();
a=200;
b=100;
c=a;
a=b;
b=c;
printf(“value of a =%d/n”,a);
printf(“ value of b=%d/n”,b);
}

Posted by: Wasim Javed

write a program to find out the greater value from two given values(NOT Operator)

main( )
{
int s,a;
printf(“/n Enter 1st integer value “);
scanf(“%d”,&s);
printf(“/n Enter 2nd Value”);
scanf(“%d”,&a);
! (s>a)? s:a;
printf( “1st is greater”): printf (“ 2nd is greater “);
getch();
}

Posted by: Wasim Javed

write a program in C to implement the “OR” operator (OR Operator)

main( )
{
int s;
char op;
pintf(“Enter Any Character/n”);
sanf(“%c”,&op);
pintf(“Enter Any integer value/n”);
sanf(“%d”,&s);
if((s>o)ll (op==’y’)ll (op==’n’))
printf(“ok, condition is True”);
else
printf(“All relational expression are false”);
}

Posted by: Wasim Javed

Write a program to find out the largest number from three given numbers(AND Operator)

Main( )
{
int r,n,b;
clrscr();
printf(“/n Enter Three Value /n”);
Scanf(“%d %d %d”,&r, &n, &b);
If (( r>n)&& (n>b))
Printf(“1st value is greater”);
Else
If((n>r)&&(n>b))
Printf(“2nd value is greater”);
Else
Printf(“3rd value is greater”);
Getch();
}


Posted by: Wasim Javed

Input two values use conditional operator to find out which value is greater. Print a message on the screen to indicate the greater value

Main( )
{
int r,b,max;
clrscr();
printf(“Enter 1st value\n”);
scanf(“%d”,&r);
printf(“Enter 2nd value\n”);
scanf(“%d”,&b);
max=(r>b)? r;b;
printf(“Greater value is =%d\n”,max);
getch();
}

Posted by: Wasim Javed

Write a program to perform the arithmetic operations by using all arithmetic operators. Also print the result on the screen( Arithmetic Operators)

Main( )
{
int p,s,m,d,r;
p=8+2;
s=8-2;
m=8*2;
d=8/2;
r=8%3;
printf(“Addition of 8 & 2 is = %d/n”,p);
printf(“Subtraction of 8&2 is=%d/n”,s);
printf(“Multiplication of 8&2 is=%d/n”,m);
printf(“Division of 8&2 is=%d/n”,d);
printf(“Remainder of 8/2 is=%d/n”,r);
}

Posted by: Wasim Javed

Difference between Buffer and Spooler

Both buffer and spoolers are used for storing data temporary. The main difference between buffer and spooler is that buffer is used for short term and spoolers are used for long term. Buffer is small and limited while spooler are large capacity to store the data as compare to buffer. For buffer it is necessary to be on line i.e. it is direct communication with computer, on the other hand spool may be either online or offline.

Posted by: Wasim Javed

Difference between paging and segmentation

Difference between paging and segmentation:-

Paging and segmentation are closed relative to each other but they have following difference.

1. Paging divides the virtual memory in physical memory areas while the segmentation divides it logically.

2. Paging divides the memory in fixed length memory areas while segmentation divides into variable length memory areas.

3. In segmentation a full logical portion of the process in loaded, but in paging information about page is loaded.

4. The segments are large length as compare to page.

5. In segmentation memory is divided into segments through software and in paging the memory in divided through hardware.

Posted by: Wasim Javed

Memory Management

Swapping:-

Swapping is a system by which use the memory efficiency mostly in time sharing system. In swapping system inactive process are kept on the backing storage, whenever required the process is allocated a time slice and process is laded into memory on computer of time slice or when process is waiting for user to response again, the process is transferred back to the backing storage.
There are two types of swapping system.

1. Simple swapping
2. Complex swapping

1. Simple swapping:-

In this system the main memory is large enough to just the operating system and enough user process and all the processes take to be swapped into a single space when they are allocated a time slice. The time for each process interaction is a follow:

Time of each interaction =Swap in time + CPU time + Swap out time = 2 * Swap time + CPU time Where swap in is the time takes by the computer to load a program from backing storage to main storage and swap out time is the time taken by computer to transfer back a program from main memory to backing storage.
By using simple swapping system we can use a small storage efficiently but main problem is that CPU is under utilized i.e. large amount of time is wasted in swap in and swap out of a program.

Thus another technique called complex sapping is used to over come the CPU under utilization.

2. Complex Swapping:-

In complex swapping when process is in main storage for processing, at the same time the next process I +1 is coming to the main storage for processing while the previous one is going at the same time, by doing so we can increase the efficiency of CPU. Thus in this system CPU will not have to want for the process of swap in or swap out, which increase the utilization of CPU. So by this system we increase the efficiency of CPU as complex to simple swapping system.

Fragmentation:-

Fragmentation is a memory management problem which occurs during swapping of process in a swapping system. When process is swap out, they left behind a free space in the memory these space are of variable length so when the process is going to be transferred its free space can not be utilized completely.

If the incoming process contains 5 KB and total space is 8 KB in these partitions as follow:

But still program cannot be loaded into the main memory although total space is greater then program space. So it causes is fragmentation called external fragmentation. Now if we have a process of 5 KB and space in partition is 8 KB, then 3 KB is left which is cannot be used for any process which cause internal fragmentation.

Segmentation:-

In memory fragmentation problem we have seen that the main memory of computer system become fragmented due to swapping of programs. The new program could not be loaded into memory though available free space is greater then program is purely planed, then we can divide the program into different segments which are certainly be smaller then complete program, and these small pieces would be better able to for into the small opening in the main store. Thus we can see that the division of virtual memory into logical memory area is called segmentation. Memory is divided into logical segments and item of the process having similar characteristics are placed in the same segment. Operating system keep segment take of all these segments which have base lentil values of each segment. A segment of process is loaded for execution when it is required one advantage of segment is that segments can be shared among different process. The information about segments in the segment table is stored sequentially.

Paging System:-Swapping:-

Swapping is a system by which use the memory efficiency mostly in time sharing system. In swapping system inactive process are kept on the backing storage, whenever required the process is allocated a time slice and process is laded into memory on computer of time slice or when process is waiting for user to response again, the process is transferred back to the backing storage.
There are two types of swapping system.

1. Simple swapping
2. Complex swapping

1. Simple swapping:-

In this system the main memory is large enough to just the operating system and enough user process and all the processes take to be swapped into a single space when they are allocated a time slice. The time for each process interaction is a follow:

Time of each interaction =Swap in time + CPU time + Swap out time = 2 * Swap time + CPU time

Where swap in is the time takes by the computer to load a program from backing storage to main storage and swap out time is the time taken by computer to transfer back a program from main memory to backing storage.
By using simple swapping system we can use a small storage efficiently but main problem is that CPU is under utilized i.e. large amount of time is wasted in swap in and swap out of a program.

Thus another technique called complex sapping is used to over come the CPU under utilization.

2. Complex Swapping:-

In complex swapping when process is in main storage for processing, at the same time the next process I +1 is coming to the main storage for processing while the previous one is going at the same time, by doing so we can increase the efficiency of CPU. Thus in this system CPU will not have to want for the process of swap in or swap out, which increase the utilization of CPU. So by this system we increase the efficiency of CPU as complex to simple swapping system.

Fragmentation:-

Fragmentation is a memory management problem which occurs during swapping of process in a swapping system. When process is swap out, they left behind a free space in the memory these space are of variable length so when the process is going to be transferred its free space can not be utilized completely.
If the incoming process contains 5 KB and total space is 8 KB in these partitions as follow:

But still program cannot be loaded into the main memory although total space is greater then program space. So it causes is fragmentation called external fragmentation. Now if we have a process of 5 KB and space in partition is 8 KB, then 3 KB is left which is cannot be used for any process which cause internal fragmentation.

Segmentation:-

In memory fragmentation problem we have seen that the main memory of computer system become fragmented due to swapping of programs. The new program could not be loaded into memory though available free space is greater then program is purely planed, then we can divide the program into different segments which are certainly be smaller then complete program, and these small pieces would be better able to for into the small opening in the main store. Thus we can see that the division of virtual memory into logical memory area is called segmentation. Memory is divided into logical segments and item of the process having similar characteristics are placed in the same segment. Operating system keep segment take of all these segments which have base lentil values of each segment. A segment of process is loaded for execution when it is required one advantage of segment is that segments can be shared among different process. The information about segments in the segment table is stored sequentially.

Paging System:-

The division of virtual memory into fixed length memory areas is called paging techniques. Each memory area is called a page. To avoid fragmentation paging is another technique. In paging system the virtual memory is divided into fixed length physical memory areas. These fixed length physical memory areas are called pages; user process is stored in these pages.
Information of the pages are stored sequentially, so to address a memory location in a particular pages, it is referenced through relative to the start address of that page so to access a memory location in a page, first page is accessed through page table in the real memory of the page then address of the memory location in referenced and used. A full page is loaded from virtual memory to real memory and is executed.

The division of virtual memory into fixed length memory areas is called paging techniques. Each memory area is called a page. To avoid fragmentation paging is another technique. In paging system the virtual memory is divided into fixed length physical memory areas. These fixed length physical memory areas are called pages; user process is stored in these pages.
Information of the pages are stored sequentially, so to address a memory location in a particular pages, it is referenced through relative to the start address of that page so to access a memory location in a page, first page is accessed through page table in the real memory of the page then address of the memory location in referenced and used. A full page is loaded from virtual memory to real memory and is executed.

Posted by: Wasim Javed

Spooling in computer

Spooling:-
Due to I/O limited jobs the C.P.U remain idle for most of the time, which effects the efficiency of the whole system. So to increase the speed of C.P.U the IBM used first time the magnetic tape and spooling system in early 1960. Spooling in the abbreviation of (Simulation Peripherals Operations Of Line). On line mean to keep all the peripherals busy at the same time. Spool can be define as a temporary storage use to remain the speed difference among the difference devices.

There arte two types of spooling.

1. off line spooling
2. online spooling

1. Off line spooling:-

In this type of spooling, the user is not interact with then jobs, when they are processed all the jobs and then associated data is stored on a fast speed device like magnetic tape using slow and expensive processor when hatch of job is formed , it is transferred to the main CPU for processing . The job and their related data is processed and the results one once again stored on the magnetic tape when output is required, the stored output data is transferred to output device.

2.Online spooling:-

There are different disadvantages of off line spooling e.g. It takes more time in reading, processing and printing. This job cannot be given a priority etc.
To overcome these problems online spooling technique is used.

In this system there is only a single processor and the spooling system existing that processor. The data is to be processed is transferred between slow device, the card reader and printer and backing storage considers a system.

Data is read from input device character by character and stored in input buffer, when buffer is filled data is transferred to backing storage, thus block of data is transferred to CPU and after processing, it is send to back store which is again transferred to the output buffer and then transferred to output device.
On line spoolings increase the efficiency of both I/O devices and CPU.

Posted by : Wasim Javed

Buffering in computer

Buffering:-
Buffer is a special kind of memory location, where data is stored temporary. Buffer is used with put devices and also with output devices.
An input buffer holds the data received from an input device before going for processing, while an output buffer holds the data received from the main memory before it is send to the output device.

Buffer is used to compensate the difference between high speed processor and low speed I/O devices.

Why Buffer is used:-

To read data directory from input devices decrease the efficiency of C.P.U.

Similarly when processor sends data to output device directly, it is a chance of loss of data because of its low speed. Therefore memory areas are needed which hold the data before processed. These memory locations are called buffers.

By using buffers C.P.U was used efficiently as well as I/O device were kept busy all the time. The time was also saved up to a limit because when C.P.U is processing at the same time I/O devices are busy for reading and writing. Buffering technique is used to operate slower devices with faster C.P.U.

Buffering Techniques:-

The techniques that are used to increase the efficiency of a processor are called as buffering techniques. Following buffering techniques are used.

Type of buffer:-

1. Single buffering.
2. Double buffering.
3. Cyclic buffering.

1. Single Buffering:-

In the techniques only one buffer is used between input and C.P.U and C.P.U to output. The buffer accepts the data from an input device character by character and when the buffers were filled then it is transferred to the C.P.U. The C.P.U accepts the data as a whole and processes it, in the mean time the empty buffer again filled character by character. The processed data is transferred to output buffer and from this buffer it is again transferred to the output device.

2. Double Buffering:-

In this technique two or more then two buffers are used.

The data is transferred from input device to the first buffer when it is filled then it is moved to C.P.U and at the same time 2nd buffer is start filling and when is filled and transferred to C.P.U the first buffer is ready for again getting data. It increases the efficiency of C.P.U.

3. Cyclic buffering:-

In double buffering technique memory space is wasted, therefore another buffering technique called cyclic buffering is used. In this technique a long single buffer is establish in which data is input by buffer pointer and outputted through user pointer. The buffer pointer writes the inputted data character by character in the buffer and the user pointer remove the data from it. A character is placed at the end of line. If the data printed is faster then the processing then the buffer pointer might over take the processing pointer and over writing may take place. In case of over writing the previous data is missed but if processing pointer or user pointer is faster then the inputting data then the processing pointer may over take the buffer pointer. This problem can be solved by using halt line pointer.
Halt line pointer indicate that last character stored in buffer which is not read for processing.


Posted by: Wasim Javed

Functions of Blood

1. Transport of respiratory Gases:

After inhaling oxygen, it reaches the lungs where it combines with hemoglobin and result in the formation oxy-hemoglobin

This oxy-hemoglobin is carried by the blood to the tissues where it breaks into Hb and O2.
The CO2 is carried by the blood to the lungs from where it passes out.

2. Transport of iron:

Inorganic iron is attached with a special type of protein which transports the iron in the body to various places.

3. Transport of nutrition:

It carries digested food material, absorbed from intestine to the tissue cells for utilization. It also carries nutritive material from storage depots to the tissues cells.

Posted by: Wasim Javed

Plasma

It is the liquid portion of the blood which is about 55% of the volume of the blood. It is mainly water which is about 90% by weight of the plasma. A large no of organic and inorganic substances are dissolved in water. Plasma is composed of organic and inorganic constituents.

(a) Inorganic constituents:

0.9% of the plasma is made up of Na, Ca ions. Which are move abundant while K, mg P and Cu ions are in lesser amounts? The cheap salt in the plasma is the Nacl.

(b) Organic Constituents:

I. 7.5% of plasma is made up of different kinds of blood portions such as serum, albumin, serum globulin, fibrinogen and prothrombin.

II. Simple :

They constitute about 0.1% in this case glucose is move abundant.

III. Product of digestion & Metabolic Wastes:

2—3% of plasma is made up of products of digestion like amino acids, fatty acids etc and metabolic wastes such as Urea, Uric acid and CO2 etc.
IV. Fats:

Neutral fats, phospholipids, cholesterol and etc.

V. Antibodies:

These are the blood proteins which provide immunity against certain diseases.

VI. Hormones:

Some blood protein is hormones interval secretion, enzymes (lipase, amylase, phosphates

VII. Coloring matter:

The yellow color of the plasma is due to small amounts of biluribin, carotene and xanthophyllin.

Posted by: Wasim Javed

Blood Pressure

Blood pressure is the force of blood against the wall of the blood vessels. It differs in various parts of the circulatory system. For example the blood pressure is normally 140 mm mercury in case where the blood leaving. The ventricles and entering the aorta under high pressure, the highest arterial blood pressure is found during the contraction of the heart ventricles. This is called systolic pressure. The lowest blood pressure is found during the relaxation of ventricles and it is called diastolic pressure, usually in the range of 70---85.

Posted by: Wasim Javed